torch.unique_consecutive

torch.unique_consecutive(*args, **kwargs)

从每个连续的等效元素组中删除除第一个元素之外的所有元素。

注意

This function is different from torch.unique() in the sense that this function only eliminates consecutive duplicate values. This semantics is similar to std::unique in C++.

参数

• input (Tensor) – 输入张量

• return_inverse (bool) – Whether to also return the indices for where elements in the original input ended up in the returned unique list.

• return_counts (bool) – Whether to also return the counts for each unique element.

• dim (int) – the dimension to apply unique. If None, the unique of the flattened input is returned. default: None

返回

A tensor or a tuple of tensors containing

• output (Tensor): the output list of unique scalar elements.

• inverse_indices (Tensor): (optional) if return_inverse is True, there will be an additional returned tensor (same shape as input) representing the indices for where elements in the original input map to in the output; otherwise, this function will only return a single tensor.

• counts (Tensor): (optional) if return_counts is True, there will be an additional returned tensor (same shape as output or output.size(dim), if dim was specified) representing the number of occurrences for each unique value or tensor.

返回类型

(Tensor, Tensor (optional), Tensor (optional))

示例

>>> x = torch.tensor([1, 1, 2, 2, 3, 1, 1, 2])
>>> output = torch.unique_consecutive(x)
>>> output
tensor([1, 2, 3, 1, 2])

>>> output, inverse_indices = torch.unique_consecutive(x, return_inverse=True)
>>> output
tensor([1, 2, 3, 1, 2])
>>> inverse_indices
tensor([0, 0, 1, 1, 2, 3, 3, 4])

>>> output, counts = torch.unique_consecutive(x, return_counts=True)
>>> output
tensor([1, 2, 3, 1, 2])
>>> counts
tensor([2, 2, 1, 2, 1])